x^2(x+1)-x(x+1)-6(x+1)=0

Solution for x^2(x+1)-x(x+1)-6(x+1)=0 equation:

Simplifying
x2(x + 1) + -1x(x + 1) + -6(x + 1) = 0

Reorder the terms:
x2(1 + x) + -1x(x + 1) + -6(x + 1) = 0
(1 * x2 + x * x2) + -1x(x + 1) + -6(x + 1) = 0
(1x2 + x3) + -1x(x + 1) + -6(x + 1) = 0

Reorder the terms:
1x2 + x3 + -1x(1 + x) + -6(x + 1) = 0
1x2 + x3 + (1 * -1x + x * -1x) + -6(x + 1) = 0
1x2 + x3 + (-1x + -1x2) + -6(x + 1) = 0

Reorder the terms:
1x2 + x3 + -1x + -1x2 + -6(1 + x) = 0
1x2 + x3 + -1x + -1x2 + (1 * -6 + x * -6) = 0
1x2 + x3 + -1x + -1x2 + (-6 + -6x) = 0

Reorder the terms:
-6 + -1x + -6x + 1x2 + -1x2 + x3 = 0

Combine like terms: -1x + -6x = -7x
-6 + -7x + 1x2 + -1x2 + x3 = 0

Combine like terms: 1x2 + -1x2 = 0
-6 + -7x + 0 + x3 = 0
-6 + -7x + x3 = 0

Solving
-6 + -7x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.